
PROGRAMMING
B–63534EN/02
19. HIGH SPEED CUTTING FUNCTIONS
519
Let the torque be x (Nm), the inertia be y(Kgm2), and the ball screw pitch
p(mm), then the acceleration A is calculated as follows:
A +
x[N @ m]
y[kg @ m
2
]
p
2p
[mm] +
x([kg @ mńsec
2
][m])
y[kg @ m
2
]
p
2p
[mm]
ĂĂ+
x p
2p y
[mmńsec
2
]
Machine specification is assumed as follows,
Ball screw pitch : 16 (mm)
Inertia : The machine inertia is to be 2.0 times higher than that
of the rotor.
(Rotor inertia: 0.0099 (Kgm
2
))
The acceleration at maximum torque is,
90 16
2p 3.0 0.0099
+ 7717[mmńsec
2
]
The acceleration at rapid traverse is,
69 16
2p 3.0 0.0099
+ 5916[mmńsec
2
]
From the above data, the parameters related to acceleration pattern is
given in the table below.
The example assumes that the acceleration is the same regardless of
whether acceleration or deceleration is in progress or whether the
movement is in the plus or minus direction.
Table. 19.10 (c) Example of setting parameters related to
acceleration pattern (1/2)
Parameter
No.
Setting Unit Remarks
Rapid
traverse
rate
1420 48000. mm/
min
The ball screw pitch is as-
sumed 16 mm, so that the rapid
traverse rate is 48000 mm/min
at the maximum speed 3000
(min
–1
).
Refer-
ence ac-
celeration
1773 194 msec Reference acceleration is
= 4124 (mm/sec
2
)
48000/60
194/1000
Speed at
P1
19541 6666 0.01% 66.66% is set at P1 because
the torque 90(Nm) is constant
up to 2000 (min
–1
) (32000mm/
min).
0.6666=32000/48000
Speeds
at P2 to
P4
19542 to
19544
0 0.01% P2 to P4 are skipped because
the torque drops almost linearly
from the speed 2000 (min
-1
) to
3000 (min
-1
).
Accelera-
tion at P0
19545,19551
19557,19563
18712 0.01% At P0, 90(Nm) can be used for
the acceleration/deceleration,
so set the ratio 7717 (mm/sec
2
)
to 4124 (mm/sec
2
).
1.8712 = 7717/4124